Sun-Synchronous Orbit Around Mars

Star Voyager

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(For the Non-Mathematician) :hide:

How would I go about putting a vessel into sun-synchronous orbit around Mars? :idk:

I just flew a less-than-5-minute-mission with a Legacy DG Mk. III for you and the answer is a highly elliptical polar orbit (my Ecc. was ~ 0.42).
 

Ajaja

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How would I go about putting a vessel into sun-synchronous orbit around Mars? :idk:
Look at "Example: calculate the inclination for a sun-synchronous polar orbit" in Doc\Technotes\gravity.pdf.
Mars sun-synchronous polar orbits with ecc=0:
Alt=100km; Incl=95.75deg.
Alt=200km; Incl=96.09deg.
Alt=300km; Incl=96.44deg.
Alt=400km; Incl=96.79deg.
 
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N_Molson

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There's an easy way to do that without having to dig into Maths.

What's a geosynchronous orbit ? It's a near-circular orbit, with an equatorial inclination near 0°, and with T = sidereal day ( 86164 seconds).

Geos means "Earth", in ancient Greek.

So, a "marsynchronous" orbit would use the same principles. For that, we need to know the duration of a sideral day on Mars. Thanks Wikipedia :

"The average length of a Martian [ame="http://en.wikipedia.org/wiki/Sidereal_day"]sidereal day[/ame] is 24h 37m 22.663s"

23 seconds will be ok, we don't need that much precision !

24*3600+37*60+23 = 88643 seconds

Now search for a circular (Ecc ~= 0), equatorial (Inc(ref EQU) ~= 0) orbit around Mars with T = 88643 sec.

That should work, unless I missed something obvious, which is possible :lol:

Edit : obviously, I didn't read carefully enough the topic, which was about Sun-synchronous orbit :beathead:

Edit2 : replace "marsynchronous" by "areosynchronous". It makes sense : Ares was the Greek god of War (Mars was the Roman one).
 
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krashkart

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Look at "Example: calculate the inclination for a sun-synchronous polar orbit" in Doc\Technotes\gravity.pdf.
Mars sun-synchronous polar orbits with ecc=0:
Alt=100km; Incl=95.75deg.
Alt=200km; Incl=96.09deg.
Alt=300km; Incl=96.44deg.
Alt=400km; Incl=96.79deg.

Thank you, Ajaja. I'll kludge together a scenario and give it a whirl. :tiphat:

Edit : obviously, I didn't read carefully enough the topic, which was about Sun-synchronous orbit :beathead:

It's all good. You earned an A+ for effort. :thumbup: [EDIT] Actually, now that I think of it you may have just helped with another thing I'd been thinking about. :lol:
 
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tblaxland

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So, a "marsynchronous" orbit would use the same principles.
FWIW, the prefix "areo-" is normally used for the Mars equivalent of "geo-", eg, "areosynchronous". Mars is the Roman god of war, Ares is the Greek god of war and "geo-" comes from the Greek for Earth. Likewise "selen-" is used for the Moon, eg, "selenography".
 

krashkart

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Okee-doke, launched a DG from Olympus base on a heading of 345 and it will be hitting ~400km in twenty minutes or so. It wasn't a perfect launch but I managed equatorial inclination of 98.71 on this first try. :)

Took off to the great white north...
picture.php


With enough practice I'll nail the inclination the first time every time. :cheers:
 

tblaxland

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With enough practice I'll nail the inclination the first time every time. :cheers:
I recommend [ame="http://www.orbithangar.com/searchid.php?ID=2802"]Launch MFD - v 1.3.3 BETA for Orbiter 2010[/ame] for that.
 

francisdrake

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If you have Orbiter installed, it is in the Doc folder.

Assuming your installation folder is called "Orbiter", it is in
Orbiter\Doc\Technotes\gravity.pdf
 

Boxx

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Don't forget to check the box Parameters > Perturbations > Nonspherical gravity sources
(because Sun-synchronous orbits are permitted by the fact that Mars, like Earth, is not spherical)
 
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